February 8, 2023
Review Of Solve The Equation 1+4+7+10+…+X=287 References. #class10#arithmeticprogressionssolve the equation :1 + 4 + 7

Review Of Solve The Equation 1+4+7+10+…+X=287 References. #class10#arithmeticprogressionssolve the equation :1 + 4 + 7 + 10 +.+ x =287 1 + 4 + 7 + 10 +.+ x =287.

The sum of first 6 terms of an a.p is 63.the ratio of the 10th term to the 20th term is 1:2. 1 + 4 + 7 +. Asked aug 26, 2020 in arithmetic progression by shyam01 (50.7k points) arithmetic progression;

### If 1 + 4 + 7 + 10 +.

Then substitute the values in the equation of sum of n terms in ap. Using sum formula of a.p i.e. Given, a = 1, d = 3 and s n = 287.

### Enter The Equation You Want To Solve Into The Editor.

1+4+7+10+.+x=287 get the answers you need, now! We have been asked to find the value of x. We get x=14,13.6(which is 14 approx;

### Now, First Term A = 1.

1 + 4 + 7 + 10 +. S n = n 2 ( a + l) s n. Ncert solutions for class 10 maths chapter 5.

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Let there be n terms so, x = a n. Last term l = x. Click the blue arrow to submit and see the result!

### Asked Apr 16, 2020 In Arithmetic Progression By Vevek01 (47.3K Points) Arithmetic Progression;

= 287, n = 14, a = 1, l = x. Apply the formula of the sum of the first n terms of ap. Asked aug 26, 2020 in arithmetic progression by shyam01 (50.7k points) arithmetic progression;  